Question

find the compound interest on rupees 10000 for 3 years at 10% per annum, compounded annually

Answer 1

S O L U T I O N :

$\underline{\bf{Given\::}}$

• Principal, (P) = Rs.10000
• Rate, (R) = 10% p.a
• Time, (n) = 3 years.

$\underline{\bf{Explanation\::}}$

As we know that formula of the compounded annually;

$\boxed{\bf{Amount=Principal \bigg(1+\frac{R}{100} \bigg)^{n}}}$

A/q

$\mapsto\tt{Amount = Principal\bigg(1+\dfrac{R}{100} \bigg)^{n}}$

$\mapsto\tt{Amount =10000\bigg(1+\dfrac{10}{100} \bigg)^{3}}$

$\mapsto\tt{Amount =10000\bigg(1+\cancel{\dfrac{10}{100} }\bigg)^{3}}$

$\mapsto\tt{Amount =10000\bigg(1+\dfrac{1}{10} \bigg)^{3}}$

$\mapsto\tt{Amount =10000\bigg(\dfrac{10+1}{10} \bigg)^{3}}$

$\mapsto\tt{Amount =10000\bigg(\dfrac{11}{10} \bigg)^{3}}$

$\mapsto\tt{Amount =10000\times \dfrac{11}{10} \times \dfrac{11}{10} \times \dfrac{11}{10}}$

$\mapsto\tt{Amount =10\cancel{000} \times \dfrac{1331}{\cancel{1000}}}$

$\mapsto\tt{Amount =Rs.(10 \times 1331)}$

$\mapsto\bf{Amount =Rs.13310}$

Now, as we know that compound Interest;

→ C.I. = Amount - Principal

→ C.I. = Rs.13310 - Rs.10000

→ C.I. = Rs.3310

Thus,

The compound Interest will be Rs.3310 .

Answer 2

Answer:

Okay.........

Step-by-step explanation:

P = ₹ 10,000

R = 10%

T = 1 (as we have to compound it per annum)

S.I = 10000×10×1 / 100

= 1000

Second.P = P + S.I

= 11000

P = ₹ 11000

R = 10%

T = 1

S.I = 11000×10×1/100

= 1100

Third.P = 11000 + 1100

= 12100

P = ₹ 12100

R = 10%

T = 1

S.I = 12100×10×1/100

= 1210

Amt. = 12100 + 1210

= 13310

C.I. = Amt – P

= 13310 – 10000

= 3310

Therefore, Compound Intrest = ₹ 3310