Question

find the compound interest on rupees 1200 for 2 years at 5% per annum​

Answer 1

Step-by-step explanation:

given that

principal = 1200 RS

rate = 5 %

time = 2years

$a = p {(1 + \frac{r}{100} )}^{t} \\ \\ = 1200 {(1 + \frac{5}{100} )}^{2} \\ \\ 1200 {(1 + \frac{1}{20} )}^{2} \\ \\ = 1200 {( \frac{20 + 1}{20}) }^{2} \\ \\ = 1200 { (\frac{21}{20}) }^{2} \\ \\ = 1200 \times \frac{21}{20} \times \frac{21}{20 } \\ \\ = 3 \times 21 \times 21 \\ \\ = 1323 \\ \\ compound \: interest \: = amount \: - principle \: \\ \\ = 1323 - 1200 \\ \\cp = 123$

Answer 2

Answer:

given that

principal = 1200 RS

rate = 5 %

time = 2years

\begin{lgathered}a = p {(1 + \frac{r}{100} )}^{t} \\ \\ = 1200 {(1 + \frac{5}{100} )}^{2} \\ \\ 1200 {(1 + \frac{1}{20} )}^{2} \\ \\ = 1200 {( \frac{20 + 1}{20}) }^{2} \\ \\ = 1200 { (\frac{21}{20}) }^{2} \\ \\ = 1200 \times \frac{21}{20} \times \frac{21}{20 } \\ \\ = 3 \times 21 \times 21 \\ \\ = 1323 \\ \\ compound \: interest \: = amount \: - principle \: \\ \\ = 1323 - 1200 \\ \\cp = 123\end{lgathered}

a=p(1+

100

r

)

t

=1200(1+

100

5

)

2

1200(1+

20

1

)

2

=1200(

20

20+1

)

2

=1200(

20

21

)

2

=1200×

20

21

×

20

21

=3×21×21

=1323

compoundinterest=amount−principle

=1323−1200

cp=123