Question

find the compound interest on rupees 12000 for 3 year at 10% per annum compounded annually​

Answer 1

for 1st year= 12000×1×10/100=1200

A=12000+1200=12200

for 2nd year= 12200×1×10/100=1220

A=12200+1220=13420

for 3rd year=13420×1×10/100=1342

A=13420+1342=14762

C.I=14762-12000= 2762

Answer 2

Step-by-step explanation:

principal=12000

time=3years

Rate=10% p.a.

Amount=Principal(100+Rate/100)power3

12000(100+10/100)power3

12000*110/100*110/100*110/100

12000*6/5*6/5*6/5

116*6*6*6

₹25056

Compound Interest= Amount-Prinicipal=25056-12000=₹13056