Question

Find the compound interest on rupees 12000 for years at 10% per annum compounded annually ​

Answer 1

Answer:

cannot be answered

time is not mentioned

Answer 2

⚫ANSWER⚫

Principal = 12000

Time = 1 year

Rate = 10 %

$= a = p( {1 - \frac{r}{100} })^{n} \\ = a = 12000(1 + \frac{10}{100} ) \\ = a = 12000( \frac{100 + 10}{100}) \\ = a = 12000 \times \frac{110}{100} \\ = a = 13200$

Now for Compound Interest,

= C.I = A - P

= C.I = 13200 - 12000

= C.I = 1200

1200 is the required answer.