Question

find the compound interest on rupees 12500 for three years at 10% for per annum compounded annually
?​

Answer 1

Step-by-step explanation:

142 hope its help you follow me

Answer 2

S O L U T I O N :

$\underline{\bf{Given\::}}$

• Principal, (P) = Rs.12500
• Rate, (R) = 10% p.a.
• Time, (n) = 3 years .

$\underline{\bf{Explanation\::}}$

As we know that formula of the compounded annually;

$\boxed{\bf{Amount=Principal\bigg(1+\frac{R}{100} \bigg)^{n}}}$

A/q

$\mapsto\tt{Amount=12500\bigg(1+\cancel{\dfrac{10}{100}} \bigg)^{3}}$

$\mapsto\tt{Amount=12500\bigg(1+\dfrac{1}{10} \bigg)^{3}}$

$\mapsto\tt{Amount=12500\bigg(\dfrac{10+1}{10} \bigg)^{3}}$

$\mapsto\tt{Amount=12500\bigg(\dfrac{11}{10} \bigg)^{3}}$

$\mapsto\tt{Amount=125\cancel{00} \times \dfrac{11}{\cancel{10} }\times \dfrac{11}{\cancel{10}} \times \dfrac{11}{10} }$

$\mapsto\tt{Amount=\dfrac{125 \times 11 \times 11 \times 11}{10} }$

$\mapsto\tt{Amount=\cancel{\dfrac{166375}{10} }}$

$\mapsto\bf{Amount=Rs.16637.5}$

Now, as we know that compound Interest ;

→ C.I. = Amount - Principal

→ C.I. = Rs.16637.5 - Rs.12500

→ C.I. = Rs.4137.5

Thus;

The compound Interest will be Rs.4137.5 .