Math, asked by Shantanu2353, 1 year ago

Find the compound interest on rupees 15625 for 1 and half years at 8% per annum,when compounded half-yearly.

Answers

Answered by Anonymous
54
Heya ✋

Given that

P = ₹15,625

R = 8 % p.a.

T = 1 and half years

= 3/2 half years

Solution

When the interest is compounded half - yearly

A = P(1+R/200)^2n

= 15,625(1+8/200)^2 × 3/2

= 15,625(200+8/200)^2

= 15,625(208/200)^2

= 15,625(26/25)^2

= 15,625 × 676/625

= ₹16,900

C.I. = A - P

= ₹(16,900 - 15,625)

= ₹1,275





Thanks :)))
Answered by RvChaudharY50
3

Given :-

  • Principal = P = Rs.15625
  • Time = T = 1(1/2) year = (3/2) years.
  • Rate = R = 8% compounded half yearly.

To Find :-

  • Compound interest = CI = ?

Solution :-

we know that, when rate is compounded half yearly,

  • Rate = Half of given rate .
  • Time = Double .

so,

  • P = Rs.15625
  • T = (3/2) * 2 = 3 years.
  • R = 8/2 = 4% compounded yearly .

now, we know that,

  • CI = P[{1 + (R/100)}^T - 1]

putting all values we get,

→ CI = 15625[{1 + (4/100)}³ - 1]

→ CI = 15625[{1 + (1/25)}³ - 1]

→ CI = 15625[(26/25)³ - 1]

→ CI = 15625[(17576/15625) - 1]

→ CI = 15625 * {(17576 - 15625)/15625}

→ CI = (15625 * 1951)/15625

→ CI = Rs.1951 (Ans.)

Learn more :-

CI in 2yr is Rs. 1600 and in 3 yrs it will be Rs. 1700. Find the rate of interest.

https://brainly.in/question/32463301

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