Question

find the compound interest on rupees 19000 for 1 year and 3 months of 8% compounded annually​

Answer 1

Answer:

Compound interest = Rs.1930.4

Step-by-step explanation:

Given: Principal Value = Rs. 19000

            Time = 1 year 3 month

             Rate  = 8% p.a.

To find: Compound interest when compounded annually

First we find Amount for 1 year using Compound interest then using its as Principal for next 3 month we find Interest using simple interest formula.

Formula of compound interest,

$A=P(1+\frac{R}{100})^n$

from given information,

n = 1 , P = 19000 , R = 8%

⇒ $A=19000(1+\frac{8}{100})^1$

         $=19000\times\frac{108}{100}$

          = Rs. 20520

Now For 3 month,

P = Rs. 20520 , R = 8% , T = 3 month = $\frac{3}{12}\,=\frac{1}{4}\:year$

$SI=\frac{PRT}{100}$

$SI=\frac{20520\times8\times\frac{1}{4}}{100}$

$SI=\frac{20520\times8}{100\times4}$

$SI=\frac{164160}{400}$

SI = Rs. 410.4

So, interest for 3 month = Rs. 410.4

Interest for 1 year = A - P(for 1 yr)

                             = 20520 - 19000

                             = Rs. 1520

⇒ Compound interest = 1520 + 410.4

                                     = Rs. 1930.4

Therefore, Compound interest = Rs.1930.4

Answer 2

Answer:

Rs.1930.4,

will be the answer

Step-by-step explanation:

hope you understood