find the compound interest on rupees 2000
at 3% per annum for 2 years(A=p×(1+r÷100)t)(CI=A-P)
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Answer:
Compound interest = Rs.121.80
Step-by-step explanation:
P = initial amount = Rs.2000
R = rate of interest per cent per year = 3
T = time period in years = 2
A = final amount at the end of T years
A = P(1 + R/100)^T
A = 2000*(1 + 3/100)^2
= 2000*(1.03)^2
= 2000*(1.0609)
Compound interest (CI) = A - P
CI = 2000*(1.0609) - 2000
= 2000*(1.0609 - 1)
= 2000*(0.0609)
= 2*1000*(0.0609)
= 2*(60.9)
= 121.8
Compound interest earned = Rs.121.80
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