Question

find the compound interest on rupees 4000 for 2 and half year at 10% per annum

Answer 1

given
p=4000
r=10%
t=2&1\2
for first year
SI=prt\100
4000*10*1\100
=400
amount p+I
4000+400
=4400
for second year (taking principal = 4400 because amount for first year is principal for second year)
SI=prt\100
4400*10*1\100
=440
amount=p+I
=4400+440
=4840
for third year( taking year=1\2)
si=prt\100
4840*10*1\100*2
=242
amount=p+I
=4840+242
= 5082
compound interest = final amount- original principal
CI=5082-4000
CI =1082