find the compound interest on rupees 4800 years at the rate of 5 pcpa compound annually
Answers
Answered by
1
Answer:
If the year is 2 then
Compound interest
=A−P
=5292−4800=Rs.492
Step-by-step explanation:
I hope it will help you
Answered by
1
Answer:
P=Rs.4800
n=2 years
R=5
As we know that,
A=P(1+ 100 R ) n
∴A=4800(1+ 100 5 ) 2
⇒A=4800( 20 21 ) 2
⇒A= 20×20 4800×21×21 =5292
Therefore,
Compound interest
=A−P
=5292−4800=Rs.492
Step-by-step explanation:
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