find the compound interest on rupees 8000 for 1 1/2 years at 10% per annum if interest being compounded half yearly
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Answer:
Principal = 8000
Rate=10%
Time=11/2
Compounded half yearly first we find the amount
A=P(1+R/200)2n
=8000(1+10/200)2×11/2
- =8000(200+10/200)11
- =8000×210/200×210/200×210/20 0×210/200×210/200×210/200×210/200×210/200×210/200×210/200×210/200
- A=13682.71
- Compound Interest=A-P
- =13682.72-8000
- =5682.72
- hence the amount is 13682.72 and compound half yearly Interest is 5682.72
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