find the compound interest on Ruppes 6200 rate of interest 4 1/2 per annum in the 3 years
Answers
Answer:
Let A be the amount and R be the interest, compounding annual
A x ((100 + R)÷100)^ 2 = 6200
A x ((100+R)÷100)^3 = 7400
Now
2÷ 1,
(100 + R)÷100 = 7400÷6200
100 + R =( 74÷62. ) X 100
100 + R = 119.3548387097
R = 19.3548387097
To find Amount,
A x( 119.3548387097/100)^2 =6200.
A x 1.4245577523= 6200
A = 6200÷1.4245577523
4,352.2279037055
In case of simple interest.
Let us take the question as involving simple interest.
Let P be the principal and R as interest rate.
Now
P + (P x 2 x R/100) = 6200
P + (Px 3xR/100) = 7400
(2) - (1)
3PR/100 - 2PR/100 = 7400 - 6200= 1200.
PR/ 100 = 1200.
(2) + (1)
2P + 3PR/100 + 2PR/100 = 7400 + 6200 = 13600.
2P + 5PR /100 = 13600.
Substituting for PR /100 as 1200.
2P +( 5 × 1200) =13600.
2P = 13600 - 6000= 7600.
P = 3800.
we have,
PR/100 = 1200.
3800× R /100 = 1200
R = 1200÷38,
31.58.
Hence the principal is 3800 and interest rate is 31.58.
Step-by-step explanation:
hope it will helpfull to you.....
please mark my ans as BRAINLIEST and follow me please.....