Question

find the compound interest on sum of R.s 8000 for 2 years at 5% per anum compounded annually​

Answer 1

$\huge \bf Given$

Principal = ₹8000

Time = 2 years

Rate = 5%

$\huge \bf To \: Find$

Compound interest

$\huge \bf Solution$

At first we will find Amount

Amount = P(1 + R/100)ⁿ

P is the Principal

R is the Rate

N is the time

Amount = 8000(1+5/100)²

Amount = 8000(105/100)²

Amount = 8000(21/20)²

Amount = 8000 × 21/20× 21/20

Amount = (8000 × 21 × 21)/(20 × 20)

Amount =(80 × 21 × 21)/4

Amount = 8820

Now,

Finding compound interest

Compound interest = Amount - Principal

Compound interest = 8820 - 8000

${\frak {\red {Compound \: Intrest = 820}}}$

Answer 2

GIVEN :-

• Principal ( P ) = Rs. 8000.
• Time ( n ) = 2 years.
• Rate ( R ) = 5% Per annum.

TO FIND :-

• The compound interest.

SOLUTION :-

Firstly , we will find the amount for the given sum,

$\implies \displaystyle \sf \:Amount = P \bigg(1 + \dfrac{R}{100}\bigg) ^{n}$

$\implies \displaystyle \sf \:Amount =800 0\bigg(1 + \frac{5}{100} \bigg) ^{2}$

$\implies \displaystyle \sf \:Amount =800 0\bigg( \frac{100 + 5}{100} \bigg) ^{2}$

$\implies \displaystyle \sf \:Amount =800 0\bigg( \frac{105}{100} \bigg) ^{2}$

$\implies \displaystyle \sf \:Amount =800 0\times \frac{11025}{10000}$

$\implies \displaystyle \sf \:Amount =8 \times \frac{11025}{10}$

$\implies \displaystyle \sf \:Amount = \frac{4 \times 11025}{5}$

$\implies \displaystyle \sf \:Amount =2205 \times 4$

$\implies \underline{ \boxed{ \displaystyle \sf \:Amount =8820}}$

Now as we know that,

$\implies \displaystyle \sf \:C.I = Amount - Principal$

$\implies \displaystyle \sf \:C.I =8820 - 8000$

$\implies \underline{ \boxed{\displaystyle \sf \:C.I =820}}$