find the compound interest on the sum of Rs 18000 at the rate of 10% per annum for 2 1/2 years
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Given,
P= 18,000
T=2.5 Years
R= 10%
To find,
CI
Solution -
CI=P(1+R/100)^t
=18000(11/10)^5/2
= 18000(121√110/1000). -- Calculating numbers raise to fraction is tricky ask another question for that sake
=2178√100
=22843.056
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