Question

find the compound interest p=2500 R=10% T=2years​

Answer 1

Answer:

Answer

Present value=₹2500

Interest rate=10% per annum

Time=2 years

To find the amount we have the formula,

Amount(A)=P(1+(R/100))

n

where P is present value, r is rate of interest, n is time in years.

Now substituting the values in above formula we get,

∴A=2500(1+10/100)

2

⇒A=2500(11/10)

2

⇒A=2500(121/100)

⇒A=25(121)

⇒A=₹3025

Now,

∴ Compound interest = A–P

=3025–2500=₹525

Answer 2

Given -

• Principal = Rs 2500
• Rate = 10℅
• Time = 2 years

To find -

• Compound interest

Solution -

• Principal (P) = Rs.2500
• Rate of interest (R) = 10 %
• Time (n) = 2 years

According to the formula

→ Amount = P(1 + R/100)ⁿ

→ A = 2500(1 + 10/100)ⁿ

→ A = 2500(10 + 1/10)²

→ A = 2500 × (11/10)²

→ A = 2500 × 11/10 × 11/10

→ A = 25 × 11 × 11

→ A = Rs.3,025

→ Amount = Rs 3,025

now

Compound interest = Amount - principal

= Rs ( 3,025 - 2500 )

= Rs 525

•°• The compound interest will be Rs 525.

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