Question

find the compound interest . p = rs4000 ,r = 6% ,t = 3 years

Answer 1

CI=4000×6×3÷100×100
=7.2%

Answer 2

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Here is your answer
As we know the formula
A = P(1+ R/100)^n
$= 4000 \times (1 + \frac{6}{100}) {}^{3} \\ = 4000 \times ( \frac{100 + 6}{100} ) {}^{3} \\ \\ = 4000 \times ( \frac{106}{100} ) {}^{3} \\ \\ = \frac{4000 \times 106 \times 106 \times 106}{100 \times 100 \times 100} \\ \\ = 4764.064$
Now
CI = A - P
= 4764.064 - 4000
= 764.064

Therefore Compound Interest is Rs. 764.064


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