Question

find the compound interest plz​

Answer 1

Answer:

416RS

Step-by-step explanation:

P=2500rs

n=2yrs

r=8%

A=P(1+r/100)^2

=2500(100+8/100)^2

=2500×108/100×108/100

=2916Rs

CI=A-P

=2916-2500

=416RS

Answer 2

Answer:

$\begin{gathered}\huge{\textbf{\textrm{\underline{\underline{\color{green}{Question:}}}}}}\end{gathered}$

• ● Find the compound Interest on Rs.2500 for 2 years at 8% per annumn compounded annually.

$\begin{gathered}\huge{\textbf{\textrm{\underline{\underline{\color{green}{Solution:}}}}}}\end{gathered}$

$\begin{gathered} \large{\textsf{\textbf{\underline{\underline{\color{brown}{Given:}}}}}}\end{gathered}$

• ● Principle = Rs.2500
• ● Rate of Interest = 8%
• ● Time = 2 years

$\begin{gathered} \large{\textsf{\textbf{\underline{\underline{\color{brown}{To Find:}}}}}}\end{gathered}$

• ● Compound Interest

$\begin{gathered} \large{\textsf{\textbf{\underline{\underline{\color{brown}{Using Formula:}}}}}}\end{gathered}$

${\large\dag}{\underline{\sf{\boxed{\sf{Amount = P \bigg \{ 1 + \dfrac{R }{100} \bigg\}^{n}}}}}}$

$\dag{\underline{\boxed{\sf{Compound \: Interest ={Amount- Principle }}}}}$

$\begin{gathered} \large{\textsf{\textbf{\underline{\underline{\color{brown}{Solution:}}}}}}\end{gathered}$

$\bigstar \:{\underline{\pmb{\frak{\red{Here}}}}}$

• ● For finding Compound Interest, firstly we need to find the Amount.

$\bigstar \: {\underline{\pmb{\frak{\red{Firstly \: Finding \: the \: Amount}}}}}$

$\quad{: \implies{\sf{Amount = \bf{P \bigg( 1 + \dfrac{R }{100} \bigg)^{n}}}}}$

• Substituting the values

$\quad{: \implies{\sf{Amount = \bf{2500 \bigg(1 + \dfrac{8}{100} \bigg)^{2}}}}}$

$\quad{: \implies{\sf{Amount = \bf{2500 \bigg(1 \times 100+ \dfrac{8}{100} \bigg)^{2}}}}}$

$\quad{: \implies{\sf{Amount = \bf{2500 \bigg(\dfrac{100 + 8}{100} \bigg)^{2}}}}}$

$\quad{: \implies{\sf{Amount = \bf{2500 \bigg(\dfrac{108}{100} \bigg)^{2}}}}}$

$\quad{: \implies{\sf{Amount = \bf{2500 \bigg({\cancel\dfrac{108}{100}} \bigg)^{2}}}}}$

$\quad{: \implies{\sf{Amount = \bf{2500 \bigg(\dfrac{27}{25} \bigg)^{2}}}}}$

$\quad{: \implies{\sf{Amount = \bf{2500 \bigg(\dfrac{27}{25} \times \dfrac{27}{25} \bigg)}}}}$

$\quad{: \implies{\sf{Amount = \bf{2500 \bigg(\dfrac{729}{625} \bigg)}}}}$

$\quad{: \implies{\sf{Amount = \bf{2500 \times \dfrac{729}{625}}}}}$

$\quad{: \implies{\sf{Amount = \bf{{\cancel{2500}} \times \dfrac{729}{\cancel{625}}}}}}$

$\quad{: \implies{\sf{Amount = \bf{4 \times 729}}}}$

$\quad{: \implies{\sf{Amount = \bf{2916}}}}$

$\begin{gathered} \dag{\overline{\underline{\boxed{\bf{\color{red}{Amount = \bf{2916}}}}}}}\end{gathered}$

• ● The Amount is Rs.2916

$\bigstar \: {\underline{\pmb{\frak{\red{Now,Finding \: the \: Compound \: Interest }}}}}$

$\quad{: \implies{\sf{Compound \: Interest = \bf{Amount- Principle }}}}$

• Substituting the values

$\quad{: \implies{\sf{Compound \: Interest = \bf{Amount- Principle }}}}$

$\quad{: \implies{\sf{Compound \: Interest = \bf{2916 - 2500 }}}}$

$\quad{: \implies{\sf{Compound \: Interest = \bf{416}}}}$

$\begin{gathered} \dag{\overline{\underline{\boxed{\bf{\color{red}{Compound \: Interest = 416}}}}}}\end{gathered}$

• ● Henceforth,The Compound Interest is Rs.416.

$\begin{gathered} \large{\textsf{\textbf{\underline{\underline{\color{brown}{Learn \ More:}}}}}}\end{gathered}$

$\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}$