Find the compound interest to the nearest rupees on Rs 10800 for 2 1/2 years at 10% per annum.
Answers
Answered by
52
amount= principle + interest
interest= amount - principle
year = 2 1/2= 5/2
amount = p(1+r/100)^n
= 10800(1+10/100)^5/2
=10800(110/100)^5/2
=10800×1.269
=13705.8
=13706 RS. (approx)
I = 13706-10800
=2906 RS.
interest= amount - principle
year = 2 1/2= 5/2
amount = p(1+r/100)^n
= 10800(1+10/100)^5/2
=10800(110/100)^5/2
=10800×1.269
=13705.8
=13706 RS. (approx)
I = 13706-10800
=2906 RS.
Answered by
14
Answer:
2984rs.
Step-by-step explanation:
- amount = p(1+r/200)²n
- 10800(1+10/200)⁵/²*²
- 1080*(21/20)*⁵
- 13783.84
- to nearest rupee is 13784 (approx)
- C. I =amt- principal
- C. I = 13784-10800
- C. I =2984rs
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