Question

find the compound interest when principal =2000 rate =20%per annum and time 3 years ​

Answer 1

QuestioN :-

Find the compound interest when

• principal (p) = 2000

• Rate (r) = 20%

• Time (n) = 3 years

AnsweR :-

$\sf \: compound \: interest \: = p \bigg(1 + \frac{r}{100} \bigg)^{n}$

$\sf \: compound \: interest \: = 2000 \bigg(1 + \frac{20}{100} \bigg) ^{3} \\ \\ \sf \: = 2000 { \bigg(1 + \frac{2}{10} \bigg) }^{3} \\ \\ \sf = 2000 \times \bigg( \frac{10+2 }{10} \bigg) ^{3} \\ \\ \sf \: = 2000 \times { \bigg( \frac{12}{10} \bigg)}^{3} \\ \\ \sf = 2000 \times {(1.2)}^{3} \\ \\ \sf \: = 2000 \times 1.728 \\ \\ \sf \boxed{ = 3456}$

Amount = 3456

Compound Interest = Amount - Principal

= 3456 - 2000

= 1456

So the compound interest is 1456.

_____________________________

Hope it will help you :)

Answer 2

Answer:

Question:-

· Find the compound interest when principal =2000 rate =20%per annum and time 3 years.

To find:-

· Compound interest

Given:-

·Principal = Rs.2,000

· Rate = 20%

· Time = 3 years.

Solution:-

⇒ $A = P (1 + \frac{R}{100} )^{n}$

       =2000 $(1 + \frac{20}{100})^{3}$

       = 2000 $( 1 + \frac{1}{5} )^{3}$

       = 2000 $(\frac{6}{5}) ^{3}$

       = 2000 × $\frac{6}{5}$  × $\frac{6}{5}$ × $\frac{6}{5}$

       = 16 × 6 × 6 × 6

⇒A = Rs.3456

⇒CI = A - P

⇒CI = 3456 - 2000

⇒CI = Rs.1456

Answer:-

·Compound interest is Rs.1456.