Question

find the compound interest when principal =50000 ,rate=10% p.a. and time=5/2 years.find the amount payable at the end if 5/2 years.​

Answer 1

Answer:

6243.20

Step-by-step explanation:

It is given that

Principal (P)=50000

Rate of interest (r)=8%p.a.=4%semi-annually

Period (n)=1½years =3semi-annually

We know that

Amount =P(1+r/100)n

Substituting the values

=50000(1+4/100)1

By further calculation =50000(26/25)³

=50000×26/25×26/25×26/25

=56243.20

Here

Compound interest=A-P

Substituting the values

=56243.20-50000

=6243.20

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Answer 2

$\huge\fbox{\underline{\underline\purple{Answer}:-}}$

$\fbox{\underline{Step~1~:}}$

Principal for 1st year ₹ 50,000 ,

Rate = 10% p.a.

$\boxed{S.I. = \frac{P \times R \times T}{100}}$

Interest for the first year = $₹ \frac{50000 \times 10 \times 1}{100} = ₹5000$

•°• Amount at the end of first year =

⠀⠀⠀⠀₹( 50000 + 5000 ) = ₹ 55000

$\fbox{\underline{Step~2~:}}$

•°•Principal for the second year ₹ 55000

Interest for the second year = $₹ \frac{55000 \times 10 \times 1}{100} = ₹5500$

Amount at the end of second year =

⠀⠀⠀⠀ ₹ ( 55000 + 5500 ) = ₹ 60500

$\fbox{\underline{Step~3~:}}$

•°•Principal for the remaining half year ₹ 60500

$\boxed{ Time= \frac{1}{2}yrs.}$

•°• Interest for the half year =$₹ \frac{60500 \times 10 \times 1}{100\times2} = ₹3025$

Amount at the end of $2 \frac{1}{2}$years =

⠀⠀⠀⠀₹ ( 60500 + 3025 ) = ₹ 63525

•°•Compund interest = ₹63525 - ₹50000 =₹13525

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Note :

Let us also calculate the Simple interest .

$S.I. = \frac{PxRxT}{100} = ₹ \frac{50000 \times 10 \times 5}{100 \times 2} = ₹12500$

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