Question

Find the compound interest when principal is Rs 8000, rate = 5% time = 2 years.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\small⇒ Compound \: \: interest (C.I)=P[(1+\frac{r}{ 100} )^t −1]$

$\textsf{P= Principal , \: r= rate, \: t= time}$

$⇒ C.I. =8000[(1+\frac{5}{100} )^2 −1]$

$=8000[\frac{25}{1000} +\frac{10}{100}]=8000[\frac{ 25+1000}{10000}]$

$⇒C.I= \frac{8}{10} [1025]=14.820.$

Answer : 14.820