find the compound interest when principal Rs 2000 rate 20% per annum and time = 2 year 3 months .
Answers
Answered by
43
principle =2000
rate =20%
time =2year 3 months = 27/24=9/8
si1=prt/100 = 2000×20×1/100=400
amount=2000+400=2400
si2=2400 ×20×1=480
compound=si1+si2
=2400+480
=2880
compound interest =400+480
= 880
480 is the answer.
hope it will help you.
please mark the brainliest.
rate =20%
time =2year 3 months = 27/24=9/8
si1=prt/100 = 2000×20×1/100=400
amount=2000+400=2400
si2=2400 ×20×1=480
compound=si1+si2
=2400+480
=2880
compound interest =400+480
= 880
480 is the answer.
hope it will help you.
please mark the brainliest.
Answered by
25
Given principal = Rs 2000
rate = 20 % , Time = 2yr 3 months
let T1=2 yr, T2 =3months = 3/12 yr =1/4yr
Find the Amount :
-------------------------
Amount=P[1+(R/100)]^T1 × [1+(T2R/100)]
= 2000[(1+(20/100)]^3×[1 + 1/4×20/100)]
= 2000 ( 120/ 100)^3 × ( 105/ 100 )
= 2000× (6/5)^3 × (21/20 )
= 2000 × ( 216/ 125 ) × ( 21 /20 )
= 9072000/2500
= Rs 3628.8
amount = 3628.8
Find the compound interest :
----------------------------------------
compound interest=amount - principal
C.I = 3628.8 - 2000 = 1628.8
therefore,
required compound interest = Rs1628.8
Answer : C.I = Rs 1628.8
--------------------------------------------------------
rate = 20 % , Time = 2yr 3 months
let T1=2 yr, T2 =3months = 3/12 yr =1/4yr
Find the Amount :
-------------------------
Amount=P[1+(R/100)]^T1 × [1+(T2R/100)]
= 2000[(1+(20/100)]^3×[1 + 1/4×20/100)]
= 2000 ( 120/ 100)^3 × ( 105/ 100 )
= 2000× (6/5)^3 × (21/20 )
= 2000 × ( 216/ 125 ) × ( 21 /20 )
= 9072000/2500
= Rs 3628.8
amount = 3628.8
Find the compound interest :
----------------------------------------
compound interest=amount - principal
C.I = 3628.8 - 2000 = 1628.8
therefore,
required compound interest = Rs1628.8
Answer : C.I = Rs 1628.8
--------------------------------------------------------
humair63:
igififogog8
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