Question

Find the compound interest when principal = Rs 3000, rate = 5% per annum and time = 2 years​

Answer 1

Step-by-step explanation:

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = time

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r)

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 100

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 )

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 10000

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 +

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 + 100

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 + 10010

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 + 10010

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 + 10010 −1)

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 + 10010 −1)=30(

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 + 10010 −1)=30( 100

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 + 10010 −1)=30( 10025

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 + 10010 −1)=30( 10025

Step-by-step explanation:Compound interest , C is given by r = rate, P = principle, n = timeC=P[(1+r) n −1]=3000[(1+ 1005 ) 2 −1]=3000(1+ 1000025 + 10010 −1)=30( 10025 +10)⇒30(104

41

41

41 )

41 )=30(

41 )=30( 10

41 )=30( 1041

41 )=30( 1041

41 )=30( 1041 )

41 )=30( 1041 )C=Rs.123.

Answer 2

C I = P[(1+I)^n -1]

C I = P[(1+I)^n -1]3000[(1+0.05)²-1]

C I = P[(1+I)^n -1]3000[(1+0.05)²-1]3000[(1.05)²-1]

C I = P[(1+I)^n -1]3000[(1+0.05)²-1]3000[(1.05)²-1]3000(0.1025)

C I = P[(1+I)^n -1]3000[(1+0.05)²-1]3000[(1.05)²-1]3000(0.1025)307.5RS.

INTEREST Rs 307.5