Question

Find the compound interest when:-
Principal = rupees 10000, Rate = 6% per annum, n = 18 months compounded half yearly.

Answer should be 927.27 just show me d method plz write f
d answer in any rough paper..

no spam answer otherwise to be reported..
best answer will be mark as brainlist..​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

= ₹10000

R= 6% = 3% (compounding halfyearly)

T= 18 months= 3 (compounding halfyearly)

$amount = p(1 + \frac{r}{100} {)}^{n}$

$a = 10000(1 + \frac{3}{100} {)}^{3}$

$a = 10000( \frac{100}{100} + \frac{3}{100} {)}^{3}$

$a = 10000( \frac{103}{100} {)}^{3}$

$a = 10000 \times \frac{103}{100} \times \frac{103}{100} \times \frac{103}{100}$

$a = \frac{1,092,727}{100}$

$a = 10,927.27$

CI = A- P

CI =₹(10927.27- 10000)

CI = ₹927.27

Hence, it's your required answer..Hope helped you....