Question

Find the compound interest when Rs. 2500 for 2 years at 12%per annum

Answer 1

Step-by-step explanation:

given that:-

principal = 2500rs

rate = 12%

time = 2 years

then according to question

$a = p( 1 + \frac{r}{100} ) {}^{t} \\ \\ = 2500 {(1 + \frac{12}{100}) }^{2} \\ \\ = 2500 {( 1 + \frac{3}{25} ) }^{2} \\ \\ = 2500 {( \frac{25 + 3}{25} )}^{2} \\ \\ = 2500 { (\frac{28}{25}) }^{2} \\ \\ = 2500 \times \frac{28}{25} \times \frac{28}{25} \\ \\ = 4 \times 28 \times 28 \\ \\ a= 3136 \\ \\ compound \: interest \: = amount - principal \\ \\ = 3136 - 2500 \\ \\ = 636 \\ \\ therefore \: comound \: interest \: is \: 636rs$

Answer 2

Answer:

636Rs

Step-by-step explanation:

A=P(1+R/100)^n

A=2500(1+12/100)^2

=2500(112/100)^2

=2500*112/100*112/100)

=3136

C.I=A-P

=3136-2500

= 636Rs