Question

find the compound interestate on rupees 16000for one year at 20% per annum, the interest being compounded quarterly

Answer 1

S.I.=1600 *1*20
2
3200

Answer 2

$Hi \: \: !!! \\ \\ Here \: \: is \: \: your \: \: answer, \\ \\ Given :- \\ Principal(P) = Rs.16000 \\ Rate \: \: of \: \: interest (R)\: = 20\% \: p.a. \\ \\ (R)\% \: per \: \: quarterly = \frac{20}{4} = 5\% \\ \\ Time(n) = 1 \: year \\ 1 \: year =( 1 \times 4)= 4 \: quarters \\ \\ \\ C.I = P[ \: {(1 + \frac{R}{100} )}^{n} - 1 \: ] \\ \\ \: \: \: \: \: \: \: = 16000 \: [ \: {(1 + \frac{5}{100} )}^{4} - 1 \: ] \\ \\ \: \: \: \: \: \: \: = 16000 \: [ \: {(1 + \frac{1}{20} )}^{4} - 1 \: ] \\ \\ \: \: \: \: \: \: = 16000 \: [ \: {( \frac{20 + 1}{20} )}^{4} - 1 \: ] \\ \\ \: \: \: \: \: \: = 16000 \: [ \: {( \frac{21}{20} )}^{4} - 1 \: ] \\ \\ \: \: \: \: \: \: = 16000 \: [ \: \frac{194481}{160000} - 1 \: ] \\ \\ \: \: \: \: \: \: = 16000 \: [ \: \frac{194481 - 160000}{160000} \: ] \\ \\ \: \: \: \: \: \: = 16000 \: [ \: \frac{34481}{160000} \: ] \\ \\ \: \: \: \: \: \: = 16000 \times \frac{34481}{160000} \\ \\ \: \: \: \: \: \: = 3448.1 \\ \\ \\ C.I = Rs.3448.1 \\ \\ \\ Hope \: \: it \: \: helps.$