Question

Find the compound intetest on 6400 for 2 years at 5.2 % per annum

Answer 1

Answer:

699,136

formula is A=P(1+r/n) power r×t

here P=6400, r=5.2/2=2.6,n=12, t=2 years

by substituting we get the answer

Step-by-step explanation:

please mark as brilliest

Answer 2

★${\purple{\huge{\boxed{\tt{Given:-}}}}}$

$\tt{ Principal=6400 rupees}$

$\tt{n= 2 years}$

$\tt{ Rate = 5.2 %}$

★${\purple{\huge{\boxed{\tt{To\:find:-}}}}}$

$\tt{Compound\: interest.}$

★${\purple{\huge{\boxed{\tt{Solution:-}}}}}$

We know that,

$\tt\boxed{Compound \: interest =p [ {(1 + \frac{r}{100}) }^{n} - 1]}$

P= principal=6400 rupees.

n = time= 2 years

r = rate = 5.2%

$compound \: interest = 6400(1 + { \frac{5.2}{100} )}^{2} - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 682.9056$

★${\purple{\huge{\boxed{\tt{Answer:-}}}}}$

Hence, the compound interest is 682.9056 .