find the compound intrest on rs 18000 for 2 years at the rate of 4%p.a?
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Answered by
2
C.I.=p(1+r/100)power n
18000(1+4/100)2
18000(26/25)2
754 ans
Answered by
1
Answer:
19468.8
Step-by-step explanation:
CI.=[p{(1+(r/100))power n ] , here n is number of years ,r = rate of interest
= [18000(1+(4/100))^2 ]
=[18000(26/25)^2 ]
=19468.8
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