Math, asked by vedantbadboi2322, 10 months ago

Find the compound intrest on rs.4000 for 2 by 1/2 year at 10 per cent per annum
with explanation ​

Answers

Answered by mohamedeshna747
1

Answer:

Principal(P) = Rs 4000

Rate of Interest(r ) = 10%

Time = 2 years and 3 months

Here first we take n = 2 years.

A = P( 1 + r /100)n Where A = Amount and n = number of years

A = 4000 (11/10)2

A = 4000 ( 121 / 100 )

A = Rs 4840

The Amount after two years = Rs 4840

Now Principal = Rs 4840

Simple interest for last 3 month i.e 1/4 year is = PRT/100 = (4840 × 10 × 1 / 4) / 100 = Rs.121

Amount after 2 years and 3 months = Rs 4840 + Rs 121 = Rs 4961

C.I = A - P

C.I = 4961 - 4000 = Rs. 961

∴ The compound interest is Rs. 961

Step-by-step explanation:

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