Find the compound intrest on rs.4000 for 2 by 1/2 year at 10 per cent per annum
with explanation
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Answer:
Principal(P) = Rs 4000
Rate of Interest(r ) = 10%
Time = 2 years and 3 months
Here first we take n = 2 years.
A = P( 1 + r /100)n Where A = Amount and n = number of years
A = 4000 (11/10)2
A = 4000 ( 121 / 100 )
A = Rs 4840
The Amount after two years = Rs 4840
Now Principal = Rs 4840
Simple interest for last 3 month i.e 1/4 year is = PRT/100 = (4840 × 10 × 1 / 4) / 100 = Rs.121
Amount after 2 years and 3 months = Rs 4840 + Rs 121 = Rs 4961
C.I = A - P
C.I = 4961 - 4000 = Rs. 961
∴ The compound interest is Rs. 961
Step-by-step explanation:
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