Math, asked by ayan9967348517, 3 months ago

find the compound intrest on rs 6400 for 2 year at 5/1 upon 2% perannum ​

Answers

Answered by asahilthakur
0

Answer:

₹723.36

Step-by-step explanation:

Principal (P) = ₹6400

Rate (R) = 5½ % = 11/2 %

Time (n) = 2 years

Amount (A) = P (1 + R/100)ⁿ

=> A = 6400 (1 + 11/200)²

=> A = 6400 (211/200) (211/200)

=> A = ₹7123.36

Compound Interest = A-P = ₹7123.36 - ₹6400 = ₹723.36


ayan9967348517: thank you
asahilthakur: most welcome..
Answered by Anonymous
3

 \sf{\underline{\underline{ \purple{ \large{Given:}}}}}

✰ Principal ( P ) = Rs. 6400

✰ Rate ( r ) =   \sf5 \dfrac{1}{2} \% =  \dfrac{11}{2} \%  \: \: p.a.

✰ Time ( n ) = 2 years

 \\ \\ \\  \sf{\underline{\underline{ \purple{ \large{To \: Find:}}}}}

✠ The compound interest.

 \\ \\ \\ \sf{\underline{\underline{ \purple{ \large{Solution:}}}}} \\ \\

First we will find amount by using formula then we will calculate compound interest by subtracting amount from the original principal.

  • The money borrowed is called the principle, the extra money paid for using lender's money is called interest and the total money paid to the lender at the end of a specified period is called amount.

  \\  \\ \twoheadrightarrow \sf{A = P{ {\bigg(1}  +  \frac{r}{100}{\bigg)}^{n} } } \\

where

  • A = amount;
  • P = principal
  • r = rate of interest compounded
  • n = number of years

\\  \\ \twoheadrightarrow \sf{A = 6400{ {\bigg(1}  +  \frac{11}{2 \times 100}{\bigg)}^{2} }}

\\  \\ \twoheadrightarrow \sf{A = 6400{ {\bigg(1}  +  \frac{11}{ 200}{\bigg)}^{2} }}

\\  \\ \twoheadrightarrow \sf{A = 6400{ {\bigg(}  \frac{200 + 11}{ 200}{\bigg)}^{2} }}

\\  \\ \twoheadrightarrow \sf{A = 6400{ {\bigg(}  \frac{211}{ 200}{\bigg)}^{2} }}

\\  \\ \twoheadrightarrow \sf{A = 6400 \times   \frac{211}{ 200} \times \frac{211}{ 200}  }

\\  \\ \twoheadrightarrow \sf{A =  {\cancel{6400}}^{32 }  \times   \frac{211}{  \cancel{200}} \times \frac{211}{ 200}  }

\\  \\ \twoheadrightarrow \sf{A =  32  \times   211 \times \frac{211}{ 200}  }

\\  \\ \twoheadrightarrow \sf{A = 6752 \times \frac{211}{ 200}  }

\\  \\ \twoheadrightarrow \sf{A  =Rs. \:  7123.36} \\ \\ \\

Now, calculate Compound interest

 \\  \sf \star  \: Compound  \: interest = A - P

\\  \sf  \star  \: Compound  \: interest = 7123.36 - 6400

\\  \sf  \star  \: Compound  \: interest = 723.36

 \\  \\  \\ \therefore {\tt{Compound  \: interest = { \green{ \underline{ \boxed{ \sf{Rs \: 723.36}}}}}}}

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