find the compound intrest rs10000 in 2 years at 4%p.a the intrest is compounded half yearly
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Answer:
₹824.32
Step-by-step explanation:
When compounded half-yearly, the rate is halved and the time is doubled.
Principal (P) = ₹10000
Rate (R) = (4÷2)% = 2%
Time (n) = (2×2) years = 4 years
Amount (A) = P (1 + R/100)ⁿ
=> A = 10000 (1 + 2/100)⁴
=> A = 10000 (51/50)⁴
=> A = ₹10824.32
Compound Interest = A-P = ₹10824.32 - ₹10000 = ₹824.32
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₹824.32 is the right answer
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