Question

Find the compound the interest on ₹25000 for 3 years at 10% p.a compound anually

Answer 1

➲. Concept :-

Compound Interest is a intrest who's First step need to found Amount.The next step subtract principal from Amount.To found amount The Basic Formula is using

$\\ \sf \big \: amount = p( \: 1 + \frac{r}{100} \: \: ) {}^{n}$

Where p = principal , R = Rate of the intrest and n = Number of times /Number of year s.

$\sf \: c.p = amount - principal$

Where, C.p = compound interest .

✰ Given :-

• Principal =25000
• Rate of interest = 10 % per annum
• Number of years = 3 years

✰To Find :-

• (Compaund Intrest )

☣ Solution :-

$\\ \sf \: \: amount = p( \: 1 + \frac{r}{100} \: ) {}^{n} \\ \\ \sf \: ➛amount \: = 25000(1 + \frac{10}{100} \: ) {}^{3} \\ \\ \sf \: ➛amount = 25000(1 + \cancel \frac{10}{100} \: ) {}^{3} \\ \\ \sf \: ➛amount = 25000( \: \frac{11}{10} \: \: ) {}^{3 } \\ \\ \sf \: ➛amount = 25000 \times ( \frac{11}{10} ) \times ( \frac{11}{10} \times ( \frac{11}{10} \: \: ) \\ \\ \sf \:➛ amount \: = 33275$

Compound Interest :-

➛Amount - principal

➛ 33275-25000

➛ 8'275

The compound interest is RS.8275

Answer 2

Answer:

The compound interest is ₹1825

Step-by-step explanation:

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