find the compund interest on 1000 at the rate of 10% per annum from 18 months when intereste in compound in half year?
Answers
Given:
- Principal = 1000
- Rate = 10%
- Time = 18 months
To find:
- The compound interest?
Solution:
By using formula,
• A = P ( 1 + R/200)^2n
Where,
- P = 1000
- R = 10%
- 2n = 3 years.
• Let the compound interest be C.I.
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« Now, By using the formula,
• A = P ( 1 + R/200)^2n
Now, Putting values,
→ A = 1000(1 + 10/200)^3
→ A = 1000(210/200)^3
→ A = 1000(1.05)^3
→ A = 1000(1.157)
→ A = 1157.625
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« Now, Let's find C.I,
As we know that,
→ C.I = A - P
→ 1157.625 - 1000
→ 157.625
∴ Hence, Compound interest on 1000 at the rate of 10% is 157.625.
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157.625
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Principal (P) = 1000
Rate (r) = 10% per annum
Number of times interest applied per time period (n) = 18 months =
Amount (A) = ?
- Compound interest
where,
C.I = Compound interest
A = final amount
P = Principal
r = interest rate
n = number of times interest applied per time period
Amount after 18 years =
As we know,
substituting the values,