Math, asked by balaganeshpandi2001, 5 hours ago

find the compund interest on 1000 at the rate of 10% per annum from 18 months when intereste in compound in half year?​

Answers

Answered by Anonymous
23

Given:

  • Principal = 1000
  • Rate = 10%
  • Time = 18 months

To find:

  • The compound interest?

Solution:

By using formula,

• A = P ( 1 + R/200)^2n

Where,

  • P = 1000
  • R = 10%
  • 2n = 3 years.

• Let the compound interest be C.I.

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, By using the formula,

A = P ( 1 + R/200)^2n

Now, Putting values,

→ A = 1000(1 + 10/200)^3

→ A = 1000(210/200)^3

→ A = 1000(1.05)^3

→ A = 1000(1.157)

→ A = 1157.625

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, Let's find C.I,

As we know that,

C.I = A - P

→ 1157.625 - 1000

→ 157.625

∴ Hence, Compound interest on 1000 at the rate of 10% is 157.625.

Answered by llMrIncrediblell
47

⠀⠀⠀⠀⠀⠀{\rm{\purple{\underline{\underline{★Required \:Answer★}}}}}

157.625

⠀⠀⠀⠀⠀{\rm{\pink{\underline{\underline{★Solution★}}}}}

{\rm{\red{\underline{\underline{Given : }}}}}

Principal (P) = 1000

Rate (r) = 10% per annum

Number of times interest applied per time period (n) = 18 months =   \rm\frac{18}{12} \:  years =  \frac{3}{2} \: years  = 1 \frac{1}{2}  \: years

Amount (A) = ?

{\rm{\blue{\underline{\underline{To \:  Find: }}}}}

  • Compound interest

{\rm{\purple{\underline{\underline{Formula \:  Used: }}}}}

 \rm \: C.I. = A - P

 \rm A  = P(1 +  \frac{r}{n} ) {}^{2n}

where,

C.I = Compound interest

A = final amount

P = Principal

r = interest rate

n = number of times interest applied per time period

{\rm{\orange{\underline{\underline{Calculations : }}}}}

Amount after 18 years =

 \rm \: P[1 +  \frac{1}{2} ( \frac{r}{100} )] {}^{2n}

 \longmapsto \rm \: 1000[1 +  \frac{1}{2} ( \frac{10}{100} )] {}^{2 \times  \frac{3}{2} }

 \longmapsto \rm \: 1000[1 +   \frac{10}{200} ] {}^{3}

\longmapsto 1000( \frac{200 + 10}{200} ) {}^{3}

\longmapsto1000( \frac{ \cancel{210}} { \cancel{200}})  {}^{3}

\longmapsto1000( \frac{21}{20} ) {}^{3}

\longmapsto1000 \times  \frac{21}{20}\times  \frac{21}{20}  \times  \frac{21}{20}

 \longmapsto1157.625

As we know,

 \rm \: C.I = A - P

substituting the values,

\longmapsto \rm \: C.I \:  = 1157.625 - 1000

\longmapsto \rm \: C.I = 157 .625

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