Question

find the compund interest on ₹18000 for 2years at the rate of 4 %p.a​

Answer 1

Answer:

Given,

Principal(P)= ₹18000

Time(T)=2years

Rate(R)=4%

Compound interest (C.I)=?

we know,

C.I = P[(1+R/100)T -1]

   =  18000[(1+4/100)2-1]

   =18000[(100+4/100)2-1]

    =18000 [(1.04)2-1]

    =18000[1.0816-1]

    =18000 x 0.0816

    =1468.8

Hence , the Compound Interest for 2 years at the rate of 4% is ₹1468.8

Step-by-step explanation:

T given in the formula C.I in the above solution is power  of (1+R/100)

Answer 2

Answer:

Rs.5805

Step-by-step explanation:

Sum = Rs.18000

Time = 2 years

Rate of interest = 15  %

A = P $(1 + \frac{r}{100} )^{n}$

A = 18000 $(1 + \frac{15}{100} )^{2}$

A = 18000 × $\frac{115}{100}$ × $\frac{115}{100}$

A = Rs.23805

∴ Compound Interest = A - P

= Rs.23805 - Rs.18000 = Rs.5805