Find the
concentration of a solution in terms
of m/m% containing 10g sugar in 100g of water?
Answers
Answer:
Hello Mate!
Case 1 ) Mass of solute = 10g
Mass of solvent = 100g
Mass by mass % = 10%
Case 2 ) Mass by solute = 10g
Mass of solution = 100g
Mass of solvent = 100g - 10g
= 90g
Concentration in first solution = 10% [ Given ]
Concentration in second soluton =
M of Solute / M of Solvent × 100 = 10 / 90 × 100
= 100 / 9 % or 11.11%
a. No concentration of two solution is different. One is 10% and another is 11.11%
b. Mass% of solution in case 1 is 10%, mass% of solution on case 2 is 11.11%.
Hence, on comparing we get that mass% of case 2 is ( 11.11 - 10 ) 1.11% greater than that of case 2.
Have great future ahead!
Answer:
Concentration ===mass of solute /mass of solvent
== 10/100=0.1%
As here, solute is sugar =10g
Solvent =100 g water.
Also this is an aquoeos solution.
Explanation: