Find the condition for the point (a,0), (h,k) and (0,b), where Abe is not equal to 0, to be colliear
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if three points are collinear it means area of traingle form by this points equal to zero
now,
area of triangle =1/2 {a (k-b)+h (b-0)+0}
0 =ak-ab+hb
ak+hb=ab
k/b +h/a =1
now,
area of triangle =1/2 {a (k-b)+h (b-0)+0}
0 =ak-ab+hb
ak+hb=ab
k/b +h/a =1
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