Question

find the condition for which the distance between A(x,y) and B(-3,5) is 6 units

Answer 1

Distance AB =((x-(-3))^2 + (y-5)^2)^1/2=6

So, x^2 + 9 + 6x  + y^2 + 25 - 10y = 36

x^2 + y^2 +6x+10y = 2

So if x^2 + y^2 + 6x + 10y = 2 then the distance between A(x,y) and B(-3,5) is
6 units.

Answer 2

Answer:

Step-by-step explanation:

AB = 6 units

AB² = 36

( x+3 )² + (y-5 )² = 36

x² + 6x  + 9 + y² - 10y + 25 =36

x² + y² + 6x - 10y  = 36 - 34

x² + y² + 6x - 10y =2

x² + y² + 6x - 10y -2 =0

I HOPE U HAVE UNDERSTOOD IT