Question

Find the condition that one root of
${ax}^{2} + bx + c = 0$
maybe the square of the other root


​

Answer 1

Answer:

(c/a)^1/3 +(c/a)^2/3 = -b/a

Step-by-step explanation:

sum of zeros= -b/a

a+a^2 = -b/a ................(1)

product of zeros = c/a

a*a^2 = c/a

a^3 = c/a

a = (c/a)1/3 ..................2

putting the value of a in eq 1 , weget

(c/a)^1/3 + (c/a)^2/3 = -b/a.

please gave a thanks or brainliest