Question

Find the condition that zeroes of the polynomial p(x)=ax²+bx+c are reciprocal of eachother. [Don't spam]

Answer 1

Answer:

A+b+c

Step-by-step explanation:

Hope it is useful to you and please follow, comment, Branillest me if you like it.

Answer 2

ax²+bx+c = 0

Let r1,r2 be the two solutions of the polynomial. Then we have

ax²+bx+c=a(x−r1)(x−r2)=ax²−a(r1+r2)x+ar1r2

so that c=ar1r2. Since one solution is the reciprocal of the other, we have r1r2=1, so that a=c. Hence, the roots are reciprocals of one another only when a=c.

{ Mark as Brainliest if it helps , it will help me too ⚡. Thank you }