Question

find the condition that zeros of polynomial p(x)=ax2+bx+c are reciprocal of each other

Answer 1

Let a and 1/a as zeros

Then product of zeros

$= \frac{constant \: term}{coefficient \: of \: {x}^{2} }$

a × 1/a = c/a

1 = c/a

a = c

That means when the roots are reciprocal of each other then a ( coefficient of x² ) will be equal to constant term .

Answer 2

Answer:sukantmishra32

Secondary SchoolMath 5+3 pts

Find the condition that zeros of polynomial p(x)=ax2+bx+c are reciprocal of each other

Report by Princepkp12341 14.02.2018

Answers

sukantmishra32

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ALTAF11

ALTAF11 Maths AryaBhatta

Let a and 1/a as zeros

Then product of zeros

= \frac{constant \: term}{coefficient \: of \: {x}^{2} }

a × 1/a = c/a

1 = c/a

a = c

That means when the roots are reciprocal of each other then a ( coefficient of x² ) will be equal to constant term .

Step-by-step explanation: