Question

Find the conjugate
(2+i^3)-(4-i^5)+(7+8i^2)

Answer 1

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To Find the conjugate of:-

(2+i^3)-(4-i^5)+(7+8i^2)

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${i}^{2} = - 1 \: and \: {i}^{3} \: or \: {i}^{5} = - i$

$(2 + {i}^{3} ) - (4 - {i}^{5} ) + (7 + 8 {i}^{2} )$

$(2 + - i) - (4 - ( - i) + (7 - 8)$

$(2 - i) - (4 + i) - 1$

$2 - i - 4 - i - 1$

$- 2 - 1 - 2i$

$- 3 - 2i$

$conjugate = 2i + 3$

Here is your answer:

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