Question

Find the conjugate of
(3-2i)(2+ 3i)/
(1 + 2i)(2-1)​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$\frac{(3 - 2i)(2 + 3i)}{(1 + 2i)(2 - i)} \\ = \frac{6 - ( - 6) + (9 + ( - 4))i}{2 - ( - 2) + ( - 1 + 4)i } \\ = \frac{12 + 5i}{4 + 3i} \\ = \frac{(12 + 5i)(4 - 3i)}{(4 + 3i)(4 - 3i)} \\ = \frac{48 - ( - 15) + ( - 36 + 20)i}{16 - 9( - 1)} \\ = \frac{63 - 16i}{25} \\ = \frac{63}{25} - \frac{16}{25} i \\ therefore \: conjugate \: is \\ \frac{63}{25} + \frac{16}{25} i$