Find the conjugate of :
(3-2i) (2+3i) / (1+2i) (2-i)
this question is from 11 class from complex number chapter
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hey here is your answer
numerator
3(2+3i)-2i( 2+3i)
6+9i-4i-6i(2)
6+5i+6=12+5i
denometor
1(2-i)+2i(2-i)
2-i+4i+2
4+3i
total
(12+5i)/(4+3i)
(12+5i)(4-3i)(4+3i)(4-3i)
{12(4-3i)+5i(4-3i)}/4*4-3i*3i
(48-36i+20i+15)/16+9
(63-16i)/25
63/25-16i/25
conjugate=63/25+16i/25
....
numerator
3(2+3i)-2i( 2+3i)
6+9i-4i-6i(2)
6+5i+6=12+5i
denometor
1(2-i)+2i(2-i)
2-i+4i+2
4+3i
total
(12+5i)/(4+3i)
(12+5i)(4-3i)(4+3i)(4-3i)
{12(4-3i)+5i(4-3i)}/4*4-3i*3i
(48-36i+20i+15)/16+9
(63-16i)/25
63/25-16i/25
conjugate=63/25+16i/25
....
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