Question

Find the conjugate of the complex number 3-4i/2i

Answer 1

Answer:

Please check it

Mark it Brainlist

FOLLOW ME

THANK YOU

Answer 2

Answer:

The conjugate is $-2+\frac{3i}{2}$.

Step-by-step explanation:

Complex numbers: Numbers that consists of two parts — a real number and an imaginary number. Such number are called complex numbers.

Conjugate of complex numbers: The numbers in which the real part remains the same, while the imaginary part will have the same magnitude but the opposite sign.

Step 1 of 1

Consider the given complex number as follows:

$\frac{3-4i}{2i}$

Rewrite the number as follows:

⇒ $\frac{3}{2i}-\frac{4i}{2i}$

⇒ $\frac{3}{2i}-2$

Further, simplify as follows:

⇒ $\left(\frac{3}{2i}\times \frac{i}{i}\right)-2$ (Rationalisation)

⇒ $\frac{3i}{2i^2}-2$

⇒ $\frac{3i}{-2}-2$ (Since $i^2=-1$)

⇒ $-2-\frac{3i}{2}$

Here, the real number is $-2$ and an imaginary number is $-3/2$.

Then, the conjugate is,

= $-2+\frac{3i}{2}$

Therefore, the conjugate of the complex number $\frac{3-4i}{2i}$ is $-2+\frac{3i}{2}$.

#SPJ2