find the conjugate of the given complex number : 3 + 2i
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Answer:
alculate ( (3 − 2i) (2 + 3i))/ ( (1 + 2i) (2 − i) ) then find its conjugate ( (3 −2i) (2+3i))/ ( (1+ 2i) (2−i) ) = (3 (2+3i)−2i (2+3i))/ (1 (2−i)+ 2i (2−i) ) = (3 × 2 +3 × 3 − 2 × 2 − 2 × 3)/ (1 × 2 + 1 × ( −) + 2 × 2 − 2 × ) = (6 + 9i − 4i + ...
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Step-by-step explanation:
conjugate of given complex number is 3-2i
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