Find the consecutive natural nos whose product is20
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Answer:5,4
Step-by-step explanation:
Let the first number is x , so another number = ( x + 1 ).
A/Q,
Product of 2 consecutive natural numbers = 20
⇒ x ( x + 1 ) = 20
⇒ x² + x = 20
⇒ x² + x - 20 = 0
⇒ x² + 5x - 4x - 20 = 0
⇒ x ( x + 5 ) - 4 ( x + 5 ) = 0
⇒ ( x + 5 ) ( x - 4 ) = 0
⇒ ( x + 5 ) = 0 ÷ ( x - 4 ) ⇒ ( x - 4 ) = 0 ÷ ( x + 5 )
⇒ ( x + 5 ) = 0 ⇒ ( x - 4 ) = 0
∴ x = -5. ∴ x = 4
So, x = 4 or -5 but it is given that x is a natural number and -5 is not a natural number as it is a negative number.
Therefore, x = 4.
First number = x = 4
Second number = ( x + 1 ) = 4 + 1 = 5
The required numbers are 4 and 5.
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