find the consecutive natural numbers whose sum is 63
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Answered by
3
x+(x+1)=63
2x=63-1
2x=62
X=31
Therefore x+1=31+1
=32
Two numbers are 31 and 32
2x=63-1
2x=62
X=31
Therefore x+1=31+1
=32
Two numbers are 31 and 32
Answered by
3
31, 32 are the consecutive natural numbers whose sum is 63.
Let one no. be x
Then other no. is x+1
x+x+1= 63
2x+1=63
2x=62
X=31
X+1=32.
Let one no. be x
Then other no. is x+1
x+x+1= 63
2x+1=63
2x=62
X=31
X+1=32.
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