Question

Find the consecutive positive integers whose sum is 63.​

Answer 1

Answer:

Two consecutive integer are

Let 1st be x and 2 be x-1

X+x-1=63

2x=64

X=32

1no.=32

2no.=x-1=32-1=31

Answer 2

Answer:- (31 and 32)

$\huge\mathfrak{Solution:}$

Let,

1st number = x

2nd number = x + 1 ( consecutive number)

$\boxed{Thus,}$

x + x + 1 = 63

2x + 1 = 63

2x = 63 - 1

2x = 62

x = 62 ÷ 2

x = 31

•°• Therefore the numbers are:

x = 31

x + 1 = 31 + 1 = 32

$\huge{= 31 \:and\: 32}$