Question

find the consecutive terms in A.P whose sum is 12 and sum 3rd and 4th term is 14 (Assume the four consecutive term in A .P are (a-d,a,a+d,a+2d)​

Answer 1

Answer:

-3,1,5and9

Step-by-step explanation:

a+a+d+a+2d+a-d

= 4a+2d=12 -(1)

sum of 3rd and 4th term is 14

a+d+a+2d

=2a+3d. = 14 -(2)

solving eq 1 or 2

1,5and94a+2d=12

4a+6d=28

sub both eq

-4d=-16

so d = 4

put the value of d on eq 1

so a will be 1

hence no will be

-3,1,5and9