Find the constant and remain when 6x^4 +11x^2 +13x^2 +27 is divided by 3x+4
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6x^4+11x^2+13^2+27
=6x^4+24x^2+27
according to remainder theorem.
3x+4=0
x=-4/3
substitute the x value
6*(-4/3)^4+24*(-4/3)^2+27
-6*256/81+24*16/9+27.
=50.7
pls mark as brainliest
=6x^4+24x^2+27
according to remainder theorem.
3x+4=0
x=-4/3
substitute the x value
6*(-4/3)^4+24*(-4/3)^2+27
-6*256/81+24*16/9+27.
=50.7
pls mark as brainliest
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